This blog started in 2023 while I was teaching first-year university mathematics at UNSW (1131 and 1231). It contains a wide range of explanations, notes, and resources covering tertiary-level mathematics topics. The easiest ways to navigate are by using the search bar or browsing through the labels/tags. If you find my content helpful and would like to support my work, a coffee donation is greatly appreciated — thank you!
Tuesday, October 31, 2023
Sunday, October 29, 2023
Tuesday, October 24, 2023
Tuesday, July 11, 2023
Monday, July 10, 2023
Sunday, July 9, 2023
Factorise $p(z)=z^5+z^4-8z^3-28z^2+16z+96$ into linear factors.
The original question was that given $-2-2i$ is a root and that $3$ other roots were real, factorise into linear factors. Since $p(z)$ has real coefficients this means the conjugate root is also a root, so both $-2-2i$ and $-2+2i$ are roots.
Here we assume that there are $3$ real roots and go from there.
Saturday, July 8, 2023
Thursday, July 6, 2023
Factorise $p(z)=z^5-5z^4+10z^3-10z^2-11z+15$ given that $z=1-2i$ is a root and that three roots are integers.(mobius)
Wednesday, July 5, 2023
Monday, July 3, 2023
Express $\cos^5t$ in terms of $\cos 5t,\cos3t,\cos t$ and express $\sin^4t$ in terms of $\cos 4t, \cos 2t$
- Other examples like this one are contained in the Algebra Notes Ch3 page 98 Example 3 and 4 ! Please also read this book, as it has many useful examples!!
- RTB - Read the Book 😎
Sunday, July 2, 2023
Thursday, June 15, 2023
Challenge:Complex reducible to quadratic equation: Solve $$z^4+2\left(a^2-b^2\right)z^2+\left(a^2+b^2\right)^2=0$$ where $a,b\in\mathbb{R}$
Solve $$z^4+2\left(a^2-b^2\right)z^2+\left(a^2+b^2\right)^2=0$$ where $a,b$ are real numbers.
Hint 1 : Put $w=z^2$ and find $w$ first. Then for each $w$, solve $z^2=w$.
Hint 2: see other posts on this label.
Answer: $z=\pm (a+ib), \pm (a-ib)$
Complex reducible to quadratics equation: Solve $$z^4+16z^2+100=0$$ .
Question: Solve $$z^4+16z^2+100=0$$ .
Show the answers are $$z=\pm(1+3i), \pm(1-3i)\ \ .$$
Complex reducible to quadratic equation: Solve $$z^4+12z^2+169=0$$