This is the factorisation of $p(z)$ into real linear factors and real quadratic factors.
ANSWER: The answer to the original question is that the complex linear factors of $p(z)$ are $$(z-1),(z+1),(z-3),(z-1+2i)(z-1-2i)\ .$$
This blog started in 2023 while I was teaching first-year university mathematics at UNSW (1131 and 1231). It contains a wide range of explanations, notes, and resources covering tertiary-level mathematics topics. The easiest ways to navigate are by using the search bar or browsing through the labels/tags. If you find my content helpful and would like to support my work, a coffee donation is greatly appreciated — thank you!
No comments:
Post a Comment